integrate(x/(1-x^2),x) and integrate(x/(x^2-1),x) don't
ask if x < 1 or x > 1. Because of this we get two
different results, when they should be equivalent,
depending on the range of integration.
Robert Dodier
2006-04-10
Dan Gildea
2011-01-24
(%i2) integrate(x/(1-x^2),x);
(%o2) -log(1-x^2)/2
(%i3) integrate(x/(x^2-1),x);
(%o3) log(x^2-1)/2
The two results are equivalent except for their sign, and a constant term of log(-1).
I don't understand the problem.
Dan Gildea
2011-02-12
SourceForge Robot
2011-02-26
This Tracker item was closed automatically by the system. It was
previously set to a Pending status, and the original submitter
did not respond within 14 days (the time period specified by
the administrator of this Tracker).
SourceForge Robot
2011-02-26