the solution of the differential equation
(1+x)*'diff(y,x)+y=1+log(1+x); is %C/(1+x)+log(1+x).
The command ode2(%,y,x)returns the following solution
: y=((x+1)log(x+1)+%C-1)/(x+1). It looks like there's
an error of sign (with the -1 which multiplicate the
constant %C)
Barton Willis
2004-07-25
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user_id=895922
This is not a bug; both solutions are correct. In Maxima's
solution substitute %c --> %c + 1. This makes the two
solutions identical. Since %c is an arbitrary parameter, the
substitution %c --> %c + 1 is okay.
Suggestion: learn how to substitute a putative solution
to an equation (DE or algebraic) into the equation to
check if it is correct.
Barton
Barton Willis
2004-07-27