#387 factor((x^(1/3)+1)^3) fails

open
nobody
Lisp Core (472)
5
2006-07-10
2003-08-19
Stavros Macrakis
No

factor((x^(1/3)+1)^3) fails, though factor((x^(1/3)+1)
^2) works.

The problem is presumably that in the ^2 case, the
powers of x are explicitly of the form n/3, whereas in the
^3 case, (x^(1/3))^3 => x, where the (1/3) is not
explicit.

Similarly for (x^(1/4)+1)^2.

Shouldn't factor normalize the exponents (like radcan)?

Discussion

  • Robert Dodier
    Robert Dodier
    2006-07-10

    Logged In: YES
    user_id=501686

    Seems to work the same way in 5.9.3cvs (although I don't
    fully understand what the problem is).

     
  • Robert Dodier
    Robert Dodier
    2006-07-10

    • labels: --> Lisp Core