factor((x^(1/3)+1)^3) fails, though factor((x^(1/3)+1)
^2) works.
The problem is presumably that in the ^2 case, the
powers of x are explicitly of the form n/3, whereas in the
^3 case, (x^(1/3))^3 => x, where the (1/3) is not
explicit.
Similarly for (x^(1/4)+1)^2.
Shouldn't factor normalize the exponents (like radcan)?
Robert Dodier
2006-07-10
Logged In: YES
user_id=501686
Seems to work the same way in 5.9.3cvs (although I don't
fully understand what the problem is).
Robert Dodier
2006-07-10