(%i1) assume(p > 0);
(%o1) [p>0]
OK:
(%i4) integrate(exp(-p * t^2),t,minf,inf);
(%o4) sqrt(%pi)/sqrt(p)
OK, but not a principle value:
(%i5) integrate(exp(-pp * t^2),t,minf,inf);
Is pp positive, negative, or zero?pos;
Principal Value
(%o5) sqrt(%pi)/sqrt(pp)
Nobody/Anonymous
2009-06-05
The difference between the two cases is in poles-in-interval. In the first case, there are no poles in the interval. In the second case, poles-in-interval thinks there are poles at minf and inf. Hence, maxima thinks we have a principal value integral.
Dieter Kaiser
2009-11-14
This problem seems to be no longer present in Maxima 5.19post:
(%i2) integrate(exp(-pp * t^2),t,minf,inf);
Is pp positive, negative, or zero?
p;
(%o2) sqrt(%pi)/sqrt(pp)
Setting the status to pending and resolution to "works for me".
Dieter Kaiser
Dieter Kaiser
2009-11-14
SourceForge Robot
2009-11-29
This Tracker item was closed automatically by the system. It was
previously set to a Pending status, and the original submitter
did not respond within 14 days (the time period specified by
the administrator of this Tracker).
SourceForge Robot
2009-11-29