From: Benjamin Root <ben.root@ou...>  20110331 16:40:18

On Sat, Mar 26, 2011 at 10:16 AM, Virgil Stokes <vs@...> wrote: > I found that > > def set_sort_zpos(self,val): > '''Set the position to use for zsorting.''' > self._sort_zpos = val > > was missing from > > class Line3DCollection(LineCollection) (in matplotlib 1.0.1): > > Now, with the above method added, add_collection3d works as it should with > line > segments, and the following will work as expected :) > > ''' > Purpose: Waterfall plot using LineCollection > Author: V.P.S. (20110326) > ''' > from mpl_toolkits.mplot3d import Axes3D > from matplotlib.collections import LineCollection > from matplotlib.colors import colorConverter > import matplotlib.pyplot as plt > import numpy as np > > np.random.seed(40040157) # Used to allow repeatable experiments (plots) > > fig = plt.figure() > ax = fig.gca(projection='3d') > > cc = [colorConverter.to_rgba(c,alpha=0.6) for c in > ('r','g','b','c','y','m','k')] > ncc = len(cc) > > nxs = 5 # Num of points to connect (nxs1 line segments) > # Generate X values > xs = np.arange(1, nxs+1, 1) > > # Create array of Y values (to be updated) > ys = np.zeros(nxs) > > # Create list of Z values > nzs = 4 # Num of Zplanes > zs = [zs+1 for zs in range(nzs)] > > # Create list of colors (cyclic) for lines > colorlist = [cc[j%ncc] for j in range(nzs)] > > segs = [] > # Generate line segments in each Zplane > for j in zs: > ys = np.random.rand(nxs) > segs.append(zip(xs, ys)) > > curves = LineCollection(segs, colors = colorlist) > > ax.add_collection3d(curves, zs=zs, zdir='y') > > ax.set_xlabel('X') # points to right  X > ax.set_xlim3d(0, nxs+1) > ax.set_ylabel('Y') # points into screen  Y > ax.set_ylim3d(0, nzs+1) > ax.set_zlabel('Z') # points up  Z > ax.set_zlim3d(0, 1) > > plt.show() > > Have a Good Day > V > > Virgil, Thanks for noticing this. There are several missing methods in the various 3D collections and artists, and I am sure we haven't found them all yet. I am currently too busy to investigate why this particular one was missing, but in about a month I will have some time to do so. Ben Root 