Work at SourceForge, help us to make it a better place! We have an immediate need for a Support Technician in our San Francisco or Denver office.
To author of launch4j,
I had installed JRE 1.6 and JRE 1.7, but EXE built from launch4j always use the newest version, which is JRE 1.7. I want my EXE to use JRE 1.6 only. Is there a way to do this?
I had set registry key: HKEY_LOCAL_MACHINE\SOFTWARE\JavaSoft\Java Runtime Environment\CurrentVersion to 1.6.
I also had set JAVA_HOME environment variable to my JRE 1.6 installation folder.
I also had made sure in PATH environment variable, I set %JAVA_HOME%\bin in the first entry, so when I invoke java.exe -version, it will call the JRE 1.6's java.exe.
But in the end, EXE built from launch4j always use JRE 1.7. I know that for sure by calling System.out.println(System.getProperty("java.version")); in my EXE code.
It seems there is no JDK Preference option to use only JRE from JAVA_HOME environment variable or from b]HKEY_LOCAL_MACHINE\SOFTWARE\JavaSoft\Java Runtime Environment\CurrentVersion registry key.
So I suggest to add a new JDK Preference option to use older JRE (if there are more than one JRE) or JRE from JAVA_HOME or the registry key in future version.
Please read the documentation:
… you may also specify the <maxVersion> to prevent it from using higher Java versions. Launch4j will always use the highest version available (in the min/max range of course)…
so, minVersion = 1.6.0, maxVersion = 1.6.0_99.