Re: [Jython-users] 2D Arrays....

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Hi=0D=0A=0D=0AThe reason why I am using numGrinderThreads  is I need to wor=
k out how=0D=0Amany threads my performance tool(Grinder) is using.  So for =
example=0D=0AThread 1 will record 1, thread record 2 and so on.=0D=0A=0D=0A=
Given the code you gave me I go the following output.  Why are there 2=0D=0A=
copies of everything=3F. =20=0D=0A=0D=0Agrinder threads is 2=0D=0A[['AAAAA'=
, 'BBBBB'], ['ZZZZZ', 'XXXXX']]=0D=0A[['AAAAA', 'BBBBB'], ['ZZZZZ', 'XXXXX'=
]]=20=0D=0A=0D=0A=0D=0AIdeally I want one copy of each record.  Also, how w=
ould I access values=0D=0Ain the this list=3F.=0D=0A=0D=0ARegards=0D=0A=0D=0A=
Raul Desai=0D=0A=0D=0A=0D=0A=0D=0A-----Original Message-----=0D=0AFrom: Ken=
t Johnson [mailto:ke...@td...]=20=0D=0ASent: 18 January 2007 18:53=0D=0A=
To: Desai, Raul=0D=0ACc: jython users=0D=0ASubject: Re: [Jython-users] 2D A=
rrays....=0D=0A=0D=0ADesai, Raul wrote:=0D=0A> Thanks for that.....however =
I still don't think what I is correct and=20=0D=0A> I can not figure it out=
=2E=0D=0A=0D=0AYour code is way more complicated than it needs to be. I'm n=
ot sure what=0D=0Ayou are doing with numGrinderThreads and userFileLineCoun=
ter - why do=0D=0Ayou open the same file repeatedly=3F - but to just read t=
he file and split=0D=0Ait into a list of lists you could do something as si=
mple as=0D=0A=0D=0AuserFile =3D open('test.csv', 'r')=0D=0AuserFileLines =3D=
 userFile.readlines()=0D=0AuserFile.close()=0D=0Aa =3D [ line.strip().split=
(',') for line in userFileLines ]=0D=0A=0D=0AIf you are trying to skip line=
s at the beginning then use userFileLines=0D=0A=3D userFile.readlines()[num=
LinesToSkip:]=0D=0A=0D=0AKent=0D=0A>=20=0D=0A> My CSV looks likes this:=0D=0A=
>=20=0D=0A> AAAAA,BBBBB=0D=0A> ZZZZZ,XXXXX=0D=0A>=20=0D=0A> And my code as =
follow:=0D=0A>=20=0D=0A>   userFile =3D open('test.csv', 'r')=0D=0A>   user=
FileLineCounter =3D 0=0D=0A>   userFileLine =3D 'null'=20=0D=0A>   xdi =3D =
''=0D=0A>   name =3D ''=0D=0A>   a =3D [[],[]]=0D=0A>   print 'grinder thre=
ads is %d' % (numGrinderThreads)=0D=0A>=20=0D=0A>   while (userFileLineCoun=
ter !=3D numGrinderThreads):=0D=0A>    userFileLines =3D userFile.readlines=
()=0D=0A>    userFileLineCounter +=3D 1=0D=0A>    if (userFileLineCounter =3D=
=3D (grinder.threadID + 1)):=0D=0A>     for i in range(0, len(userFileLines=
)):=0D=0A>      print 'Thread Data Line %d: %s' % (i, userFileLines[i])=0D=0A=
>      # split the string into each individual data item=0D=0A>      lineDa=
ta =3D userFileLines[i].split(',')=0D=0A>      for j in range(0, len(lineDa=
ta)):=0D=0A>       print 'PK %d value: %s' % (j, lineData[j])=0D=0A>       =
a[0].append(lineData[j])=0D=0A>       a[1].append(lineData[j])=0D=0A>    br=
eak=0D=0A>   print a=0D=0A>   userFile.close()=0D=0A>   print 'file closed'=0D=
=0A>=20=0D=0A> The output is=0D=0A>=20=0D=0A> grinder threads is 2=0D=0A> [=
[], []]=0D=0A> file closed=0D=0A> Thread Data Line 0: AAAAA,BBBBB=0D=0A> =0D=
=0A> XDI1 0 value: AAAAA=0D=0A> XDI1 1 value: BBBBB=0D=0A>=20=0D=0A> Thread=
 Data Line 1: ZZZZZ,XXXXX=0D=0A> XDI1 0 value: ZZZZZ=0D=0A> XDI1 1 value: X=
XXXX=0D=0A> [['AAAAA', 'BBBBB\n', 'ZZZZZ', 'XXXXX'], ['AAAAA', 'BBBBB\n', '=
ZZZZZ',=0D=0A=0D=0A> 'XXXXX']] file closed=0D=0A>=20=0D=0A>=20=0D=0A> I wou=
ld expect the List to look like:=0D=0A>             =20=0D=0A> [['AAAAA', '=
BBBBB]['ZZZZZ', 'XXXXX']]=0D=0A>=20=0D=0A> Any suggestions=3F.=0D=0A>=20=0D=
=0A> Regards=0D=0A>=20=0D=0A> Raul=0D=0A>=20=0D=0A>=20=0D=0A>=20=0D=0A> ---=
--Original Message-----=0D=0A> From: jyt...@li...urceforge=
=2Enet=0D=0A> [mailto:jyt...@li...] On Behalf=
 Of Leo=20=0D=0A> User=0D=0A> Sent: 18 January 2007 17:16=0D=0A> To: jython=
 users=0D=0A> Subject: Re: [Jython-users] 2D Arrays....=0D=0A>=20=0D=0A> Yo=
u can probably just use list within a list:=0D=0A> list =3D [[],[]]=0D=0A>>=
>> a =3D [[],[]]=0D=0A>>>> a=0D=0A> [[], []]=0D=0A>>>> for z in xrange(10):=0D=
=0A> ...     a[0].append(z)=0D=0A> ...     a[1].append(z)=0D=0A> ...=0D=0A>=
>>> a=0D=0A> [[0, 1, 2, 3, 4, 5, 6, 7, 8, 9], [0, 1, 2, 3, 4, 5, 6, 7, 8, 9=
]]=0D=0A>=20=0D=0A> or maybe use jarray.=0D=0A>=20=0D=0A> Or you can use on=
e list/array and calculate the index.=0D=0A>=20=0D=0A> leouser=0D=0A>=20=0D=
=0A>=20=0D=0A> --- "Desai, Raul" <Rau...@an...> wrote:=0D=0A>=20=0D=
=0A>> Hi Guys=0D=0A>>=0D=0A>> If I am reading a CSV file which has 2 column=
s and 10 records, I can=20=0D=0A>> I=0D=0A>=20=0D=0A>> create a 2D Array wh=
ich will hold this data=3F.  The 2D array will be=20=0D=0A>> populated in a=
 For loop which I have.  Also how can access for=20=0D=0A>> example=0D=0A> =0D=
=0A>> certain values for a  nth record=3F.=0D=0A>>=0D=0A>> I have not been =
able to hold of much information on my problem.  Any=20=0D=0A>> assistance =
will be greatly appreciated.=0D=0A>>=0D=0A>> Regards=0D=0A>>=0D=0A>> Raul=0D=
=0A>>=0D=0A>> e.net/lists/listinfo/jython-users=0D=0A>>=0D=0A>=20=0D=0A> =0D=
=0A> -----Original Message-----=0D=0A> From: jyt...@li...u=
rceforge.net=0D=0A> [mailto:jyt...@li...] On =
Behalf Of Leo=20=0D=0A> User=0D=0A> Sent: 18 January 2007 17:16=0D=0A> To: =
jython users=0D=0A> Subject: Re: [Jython-users] 2D Arrays....=0D=0A>=20=0D=0A=
> You can probably just use list within a list:=0D=0A> list =3D [[],[]]=0D=0A=
>>>> a =3D [[],[]]=0D=0A>>>> a=0D=0A> [[], []]=0D=0A>>>> for z in xrange(10=
):=0D=0A> ...     a[0].append(z)=0D=0A> ...     a[1].append(z)=0D=0A> ...=0D=
=0A>>>> a=0D=0A> [[0, 1, 2, 3, 4, 5, 6, 7, 8, 9], [0, 1, 2, 3, 4, 5, 6, 7, =
8, 9]]=0D=0A>=20=0D=0A> or maybe use jarray.=0D=0A>=20=0D=0A> Or you can us=
e one list/array and calculate the index.=0D=0A>=20=0D=0A> leouser=0D=0A> =0D=
=0A>=20=0D=0A> --- "Desai, Raul" <Rau...@an...> wrote:=0D=0A>=20=0D=
=0A>> Hi Guys=0D=0A>>=0D=0A>> If I am reading a CSV file which has 2 column=
s and 10 records, I can=20=0D=0A>> I=0D=0A>=20=0D=0A>> create a 2D Array wh=
ich will hold this data=3F.  The 2D array will be=20=0D=0A>> populated in a=
 For loop which I have.  Also how can access for=20=0D=0A>> example=0D=0A> =0D=
=0A>> certain values for a  nth record=3F.=0D=0A>>=0D=0A>> I have not been =
able to hold of much information on my problem.  Any=20=0D=0A>> assistance =
will be greatly appreciated.=0D=0A>>=0D=0A>> Regards=0D=0A>>=0D=0A>> Raul=0D=
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