Hi all
       I built a simple applet in jython which on keyTyped event sends the typed character to the server(written in python listining on 80 port).
       The archive for the applet is a jar file
       But when I try to view it on a browser , it gives me the following error's
      java.security.AccessControlException: access denied (java.net.SocketPermission 192.168.2.40:80 connect,resolve)
        at java.security.AccessControlContext.checkPermission(AccessControlContext.java:264)
        at java.security.AccessController.checkPermission(AccessController.java:427)
        at java.lang.SecurityManager.checkPermission(SecurityManager.java:532)
        at java.lang.SecurityManager.checkConnect(SecurityManager.java:1034)
        at java.net.Socket.connect(Socket.java:501)
        at java.net.Socket.connect(Socket.java:457)
        at java.net.Socket.<init>(Socket.java:365)
        at java.net.Socket.<init>(Socket.java:178)
        at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method)
        at sun.reflect.NativeConstructorAccessorImpl.newInstance(NativeConstructorAccessorImpl.java:39)
        at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(DelegatingConstructorAccessorImpl.java:27)
        at java.lang.reflect.Constructor.newInstance(Constructor.java:494)
        at org.python.core.PyReflectedConstructor.__call__(PyReflectedConstructor.java)

The code for the applet is:
from java.applet import Applet
from java.awt.event import KeyListener
from java.awt import *
from java.net import Socket
from java.io import *

class shell1(Applet,KeyListener):
        key=''
        def init(self):
                self.addKeyListener(self)
                self.socket=csSocket()
        def keyTyped(self,keyEvent):
                self.key=keyEvent.getKeyChar()
                print self.key
                self.socket.csWrite(self.key)
                self.repaint()
        def paint(self,g):
                g.setColor(Color.black)
                g.setColor(Color.white)
                g.drawString(str(self.key),50,50)
        def keyReleased(self,keyEvent):
                pass
        def keyPressed(self,keyEvent):
                pass
        def stop(self):
                self.cs.close()
class csSocket(Socket):
        HOST='192.168.2.40'
        PORT=80
        def __init__(self):
                self.cs=Socket(self.HOST,self.PORT)
                self.outputStream=cs.getOutputStream()
                self.inputStream=cs.getInputStream()
        def csRead(self):
                self.inputStream.read()
        def csWrite(self,data):
                self.outputStream.write(data)
        def csClose(self):
                self.cs.close()
The server is running on 192.168.2.40:80 and the applet on 192.168.2.31
I compiled the .py file with following syntax
jythonc --jar shell1.jar -a -d -J "-source 1.2" shell1.py
Then on the local machine where the applet resides I generated a key with:
keytool -genkey //I did'nt gave the key name and so it created key with keyname as 'mykey'
Then I fired the following commands:
keytool -selfcert
jarsigner shell1.jar mykey
It exited successfully // That means shell1.jar got signed(am I right or wrong)
But still when I view the applet it repeats the above mentioned error's

Do some one have the solution for this
Would be grateful if I get some
-
Regards
-
Rishi Pathak