[joe] calling joe from xargs

[Moritz B. <bar...@gm...>]

Hi, me again,

another problem, very very riddling:

Sometimes, I construct a list of files to be edited, e.g. with "find" and
"grep":

$ find -type f ! -name "*~" | xargs grep "something" | cut -d: -f1

Piping this list to "xargs joe" should call joe with these filenames as
arguments (assuming the list is short enough). No fiddling with file
descriptors or anything, or?

Yet
$ find -type f ! -name "*~" | xargs grep "something" | cut -d: -f1 | xargs joe
fails miserably, joe mucking up the terminal a bit (though you see the
effort of joe opening some virtual windows with these files).

Calling
$ joe `find -type f ! -name "*~" | xargs grep "something" | cut -d: -f1`
is fine, though.

Any explanation? I suppose it _must_ be something with joe losing some file
descriptors or the likes... And shouldn't be the case!

(Platform is Linux, shell is bash-2.05, BTW.)

Thanks,
Moritz