Jonathan, I checked in some code for you. The solution is just to use absolute paths, not relative ones. This works for me both in Eclipse and from the Jar file.

 Bytes[] data = getResourceAsBytes("org/openscience/jmol/app/images/angleButton.gif")
 

  private static byte[] getResourceAsBytes(String fullPath) {
    byte[] buf = new byte[1024];
    byte[] bytes = new byte[4096];
    BufferedInputStream bis = new BufferedInputStream(ClassLoader
        .getSystemResourceAsStream(fullPath));
    int len = 0;
    int totalLen = 0;
    try {
      while ((len = bis.read(buf)) > 0) {
        totalLen += len;
        if (totalLen >= bytes.length)
          bytes = ArrayUtil.ensureLength(bytes, totalLen * 2);
        System.arraycopy(buf, 0, bytes, totalLen - len, len);
      }
      buf = new byte[totalLen];
      System.arraycopy(bytes, 0, buf, 0, totalLen);
    } catch (Exception IOException) {
      Logger.error("WebPanel IO ERROR reading resource " + fullPath);
      return null;
    }
    return buf;
  }


On Wed, Apr 28, 2010 at 8:06 PM, Jonathan Gutow <gutow@uwosh.edu> wrote:
I've run into a problem using some of the internal resources inside the Jmol.jar for WebExport.  If anybody knows what I'm doing wrong please let me know.

Running inside Eclipse my code works.
As a compiled .jar I find that the resource URL is null instead of a usable value.
Note it continues to work for things inside the WebExport.html part of the jar.  I assume this may have to do with the fact that WebExport is below the resources I am trying to access in the jar structure.  I have not been able to figure out what to do.  Should I be getting the URL with a call like object.getParent...?

Here's the piece of code.

object = this (the WebExport object)
fileName = ( button.png, which works for files in WebExport.html, or ../image/button.png or org/openscience/jmol/app/images/ neither of the last two work in the compiled .jar, but all three work in Eclipse)
flagError=True.

static URL getResource(Object object, String fileName, boolean flagError) {
   URL url = null;
   if (!fileName.contains("/"))fileName="html/"+fileName;
   try {
     if ((url = object.getClass().getResource(fileName)) == null && flagError)
       System.err.println("Couldn't find file: " + fileName);
   } catch (Exception e) {
     System.err.println("Exception " + e.getMessage() + " in getResource "
         + fileName);
   }
   return url;
 }

Thanks,
Jonathan

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