From: H.N. de Ridder <hnridder@gr...>  20131231 16:05:35

Hi, no, the ConnectivityInspector ignores the direction of the edges. So if your graph has edges s>t>u and you call connectedSetOf(t), you will get {s, t, u} as the result. If you want to get precisely those nodes that are reachable from t (traversing edges in the "proper" direction only), you can do a breadth first search from t with BreadthFirstInspector. If you want to do this for many nodes, it may be faster to first calculate the transitive closure of the graph and then check the outneighbours of your node. The transitive closure G' of G has an edge u>v precisely when there is a path u==>v in G. Do you have a unique top level term from which all useful terms are reachable, or is your construction more complicated? Regards, Ernst  Reply message  From: org.jgrapht@... To: <jgraphtusers@...> Subject: [jgraphtusers] Maximally connected component for dependencies? Date: Mon, Dec 30, 2013 21:32 'Lo. As mentioned previously, I'm using jgrapht to handle dependencies in a small programming language I'm developing. I was originally only using the library to handle module imports, but I've since moved to using the library to track dependencies between all types and terms in the language. For example: In the term graph, if a term t contains a reference to a term u, the graph contains an edge from t > u. I'd like to use the connectivity information during code generation to exclude all unreferenced terms from the final program. Is the ConnectivityInspector the right way to handle this? Specifically, given a "top level" term t, I want all of those terms to which t refers, and the terms to which those terms refer, and so on, and so on, excluding any otherwise unreferenced terms. I think that basically means instantiating a new ConnectivityInspector for the term graph and then calling connectedSetOf(t)? Am I correct in thinking that, given that the graph is directed and acyclic, that I won't get terms that depend on t (vertices with outgoing edges to t)? If that's correct, then presumably I *would* get those terms if the graph was undirected? Apologies if these are blindingly obvious questions. I'm not all that familiar with graph algorithms. M  Rapidly troubleshoot problems before they affect your business. Most IT organizations don't have a clear picture of how application performance affects their revenue. With AppDynamics, you get 100% visibility into your Java,.NET, & PHP application. Start your 15day FREE TRIAL of AppDynamics Pro! http://pubads.g.doubleclick.net/gampad/clk?id=84349831&iu=/4140/ostg.clktrk _______________________________________________ jgraphtusers mailing list jgraphtusers@... https://lists.sourceforge.net/lists/listinfo/jgraphtusers 