RE: [Exist-open] XML declaration with XQuery

[Doug B. <do...@we...>]

Thanks, David, your example will probably solve my problem. I had tried =
just
adding the declaration like your example, as opposed to my document
constructor attempt, but failed on both your caveats. I wonder if the
document constructor will work with a new snapshot? If it does I'll =
mention
it to the list. It will probably be a day or so before I install the
snapshot.
=20
Doug
=20
-----Original Message-----
From: David Mundie [mailto:mu...@an...]=20
Sent: Monday, June 07, 2004 5:25 AM
To: do...@we...
Cc: exi...@li...
Subject: Re: [Exist-open] XML declaration with XQuery


Here's what I'm using:

<?xml version=3D"1.0" encoding=3D"UTF-8"?>,
<?xml-stylesheet type=3D"text/css" href=3D"http://localhost/test.css"?>,
<test>

{ for $speech in document('/db/sanskrit/g.xml')//entryFree[form/orth =
&=3D
'kl?p*']
return $speech }
</test>

Two caveats:=20

(a) the commas are essential;
(b) you need a relatively recent snapshot - there was a parser bug =
involving
processing instructions until sometime in May.

- dam

On 2004-Jun-06, at 23:32, Doug Black wrote:



How do I get an XML declaration, e.g.. <?xml version=3D"1.0" ?> at the =
top of
my results returned from XQuery so that the browser will recognize the
results as XML. I believe I'm looking for something to add to the =
XQuery.
I've tried to use a document constructor but can't even get past syntax
errors, e.g.

document {=20
   return=20
      <collection>=20
        (: more XQuery stuff :)=20
      </collection>=20
}=20



Thanks,=20

Doug=20

Doug Black=20
West Rock Visions=20
755 Prospect St. #205=20
New Haven, CT 06511=20
Mobile and Office: 203-676-5228=20
Home: 203-389-0184=20

do...@we...=20
 =20