Webware for Python

Hi Marcus.  Glad you find the software useful.

The Short-Bad answer to your question is: No, you can't do this in WebKit.

The Short-Good answer is:  We can add this in no time!

Isn't python great!

At first I didn't see the point, you could just use form variables.  But I guess this would be useful for giving out a URL without ?'s in it.


Would you let us know how java provides the extra path info in the HTTPRequest, just for reference (we may do it differently)


Chuck-

If you want to add this, my thought for the algorithm is:

At the end of Application.serverSidePathForRequest() (after finding the context), we add a   "if not os.path.exists(ssPath):"

Then, do the extension testing.

Then, pull off the rightmost item and do the extension test, until we find the Servlet or get to ''.  If we find the servlet, we add the extra request path info to the HTTPRequest._fields dict, with a key of "extraPathInfo", or something like that.


Jay





> Congratulations to the release! I have played with it a 
> little with the intention of using it for RAD prototyping 
> of a site I will be working on and it looks promising.
> 
> I  wonder about one thing though. My need would be to call 
> a certain servlet with an additional path that would be 
> used as a parameter, I have done this with java servlets, 
> and it can be a nice way of hiding the application structure 
> from the users.
> 
> For example
> /cgi-bin/WebKit.cgi/Bands/Metallica/LovesNapster
> 
> is sent to the Bands.py servlet with the rest as a parameter. 
> Using mod_rewrite you could even hide the cgi-bin and WebKit.cgi 
> parts. I didn't get this to work, did I miss something or shouldn't 
> it be possible in WebKit.
> 
> Marcus Ahlfors
> mahlfors@...
> 
> 
> 
> 
> _______________________________________________
> Webware-discuss mailing list
> Webware-discuss@...
> http://lists.sourceforge.net/mailman/listinfo/webware-discuss
> 
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Re: [Webware-discuss] Servlet path translation From: Chuck Esterbrook <echuck@mi...> - 2000-06-07 19:01 At 02:07 PM 6/7/00 +0000, Jay Love wrote: >Hi Marcus. Glad you find the software useful. > >The Short-Bad answer to your question is: No, you can't do this in WebKit. > >The Short-Good answer is: We can add this in no time! > >Isn't python great! > >At first I didn't see the point, you could just use form variables. But I >guess this would be useful for giving out a URL without ?'s in it. > > >Would you let us know how java provides the extra path info in the >HTTPRequest, just for reference (we may do it differently) > > >Chuck- > >If you want to add this, my thought for the algorithm is: > >At the end of Application.serverSidePathForRequest() (after finding the >context), we add a "if not os.path.exists(ssPath):" > >Then, do the extension testing. > >Then, pull off the rightmost item and do the extension test, until we find >the Servlet or get to ''. If we find the servlet, we add the extra >request path info to the HTTPRequest._fields dict, with a key of >"extraPathInfo", or something like that. > > >Jay Sounds fine to me. For increased efficiency, you could do it the left to right instead. This might tie into our Context/Application discussions, so that an entry in our "directory mapping" dictionary would specify that everything that started with /Bands went to a particular servlet. I think this is how Java does it in fact. -Chuck

Re: [Webware-discuss] Servlet path translation From: Marcus Ahlfors <mahlfors@ra...> - 2000-06-08 12:02 Ok, I have investigated a little. In the Java Servlet Specification page 29, a request is made up of: requestURI = contextPath+servletPath+pathInfo Where pathInfo is the extra path after the servlet name. There is some examples in the specs. I don't know but I suspect that java servlets all must reside in one directory. That would of course simplify the parsing. If played around a little along Jay's advices, this is a works-for-me solution. But nothing that should be used in a final version. I didn´t put that much effort in it since I don't know all details on what the function is supposed to do. def serverSidePathForRequest(self, request, urlPath): ''' Returns what it says. This is a 'private' service method for use by HTTPRequest. ''' + # Create context path + tail = urlPath + pathInfo = "" + try: + prepath = self._Contexts['contextName'] + except KeyError: + prepath = self._Contexts['default'] + if not os.path.isabs(prepath): + prepath = os.path.join(self.serverDir(), prepath) + + # Look for servlets from right to left + while tail != '': + ssPath = os.path.join(prepath, tail + ".py") + if os.path.exists(ssPath): + request._fields['pathInfo'] = pathInfo + return ssPath + tail,head = os.path.split(tail) + pathInfo = os.path.join(head,pathInfo) ssPath = self._serverSidePathCacheByPath.get(urlPath, None) if ssPath is None:

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