On Mon, 10 Sep 2007, Yujie wrote:
> I know the degree of freedom numbering is done element-by-element. I also
> know if one uses high order shape functions (p>1), he will obtain more
> solution number than the nodes in the mesh. However, now I use First-order
> Lagrange shape functions, In one tetrahedron element, to my knowledge, one
> varialbe is relevant to one vertex of tetrahedron. Is it right?
In this case, you can get the solution corresponding to a single Node
Unlike the two methods which I previously suggested to you, this
method will fail on non-vertex nodes on non-Lagrange elements, on
interior nodes on quadratic Lagrange elements, and on non-vertex nodes
on non-isoparametric Lagrange elements. If that's what you want, go
nuts, but I hope you're beginning to see why I must again turn down
your emailed offers to let me debug your application codes for free.