Saxon XSLT and XQuery Processor

Hi All,

I am trying to create a Java extension function (which accepts a  
string and returns a Node) and call it from an XSLT template. I have  
managed to successfully do that before with Saxon but now with my  
very simple example I am having problems and not sure why.

I am using Saxon 8.4 and JDK 1.4.2-50.

My stylesheet:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
                 version="1.0">
<xsl:output method="html" version="4.0"/>

<xsl:variable name="genericLinker" select="genericLinker:new()"  
xmlns:genericLinker="java:GenericLinker"/>

<xsl:template match="text()">
   <xsl:copy-of select="genericLinker:addLinks($genericLinker,.)"  
xmlns:genericLinker="java:GenericLinker"/>
</xsl:template>
</xsl:stylesheet>

My GenericLinker java class:
import org.w3c.dom.Element;
import org.w3c.dom.Node;
import org.w3c.dom.Document;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;

public class GenericLinker{
     public GenericLinker (){
     }

     public Element test(String a){
        Element returnNode=null;
         try{
             org.w3c.dom.Document doc =  
DocumentBuilderFactory.newInstance().newDocumentBuilder().newDocument();
             returnNode = doc.createElement("div");
             returnNode.appendChild(doc.createTextNode("test"));
         }
         catch(Exception e ){
         }
         return returnNode;
     }
}

But applying the stylesheet above to a test document returns  
something like:
&lt;div&gt;test&lt;/div&gt;

I was hoping to get back a proper <div> node, instead of the returned  
result. Can anybody spot an error either with my stylesheet or the  
Java code?

Regards,
Yeliz
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School of Computer Science
The University of Manchester
Manchester
M13 9PL
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