The expression parser, which is used for variable default values, is
a bit limited. There are many things it cannot handle aside from
I'd like to re-write the C++ parser using wisent, for which
arithmetic syntax can be well supported.
>>> bread <breaddawson@...> seems to think that:
>I found that if a variable will be missed from the completions if it is
>declared using other pre-defined vars.
> int bread_a = 1;
> int bread_b = 2;
> int bread_c = bread_a + bread_b;
> int result = bread_
>the completions will only have "bread_a" and "bread_b", bread_c is missed.
>I'm not sure if this is my own preference, though. Fortunately most of the
>time i can remember what the var naem is. :)